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Statement I : The oxidation number of boron in BF₃ is +3
Statement II : Boron cannot form a cation

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Both the statements are true

Both the statements are false

I is false and II is true

I is true and II is false

answer is A.

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Detailed Solution

$B{F_3}$

$x + 3left( { - 1} right) = 0$

$x = + 3$

$therefore$ the oxidation state of B in BF₃ is +3.

→Boron can't form caion ,due to its small size and high sum of first three ionisation energies.Therefore it does not lose its three valency electrons and does not form B⁺³cation.

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