Statement – I: The shortest distance between the skew lines $\frac{x - 1}{2} = \frac{y - 1}{- 1} = \frac{z - 0}{1} a n d \frac{x - 2}{3} = \frac{y - 1}{- 5} = \frac{z + 1}{2} i s \frac{10}{\sqrt{2}}$
Statement – II: Two lines are skew lines if there exists no plane passing through them

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Both the statements are true and Statement-2 is correct explanation of statement-1

Both the statements are true and Statement-2 is not the correct explanation of statement-1

Statement -1 is true and Statement- 2 is false

statemen-1 is false and Statement -2 is true

answer is D.

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Detailed Solution

shortest distance between the given lines

$\frac{x - 1}{2} = \frac{y - 1}{- 1} = \frac{z - 0}{1} a n d \frac{x - 2}{3} = \frac{y - 1}{- 5} = \frac{z + 1}{2} i s \frac{10}{\sqrt{59}}$

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