Statement I: The surface charge densities of two spherical conductors of different radii are equal. Then the electric field intensities near their surface are also equal.
Statement II: Surface charge density is equal to charge per unit area.

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Both statements I and II are correct

Statement-I is correct and statement-II is incorrect

Both statements I and II are incorrect

Statement-I is incorrect and statement-II is correct

answer is A.

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Detailed Solution

$As σ_{1} = σ_{2} (Given) ∴ \frac{q_{1}}{4 {πr}_{1}^{2}} = \frac{q_{2}}{4 {πr}_{2}^{2}}, or \frac{q_{1}}{q_{2}} = \frac{r_{1}^{2}}{r_{2}^{2}} [Let r_{1} {andr}_{2} be two different radii]$

Then the ratio of electric field intensities near the surface of spherical conductor,

$\frac{E_{1}}{E_{2}} = \frac{q_{1}}{4 {πε}_{0} r_{1}^{2}} \times \frac{4 {πε}_{0} r_{2}^{2}}{q_{2}} = \frac{q_{1}}{q_{2}} \times \frac{r_{2}^{2}}{r_{1}^{2}} = 1, i.e., E_{1} = E_{2}$ .