Statement-I: Xe-atom in ${XeF}_{2}$ assumes sp-hybrid state.
Statement-2: ${XeF}_{2}$ molecule does not follow octet rule.

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Statement-I is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-I.

Statement-I is True, Statement-2 is True, Statement-2
Is NOT a correct explanation for Statement-I.

Statement-I is False, Statement-2 is True

Statement-I is True, Statement-2 is False

answer is D.

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Detailed Solution

The Xe molecule is in an excited state in ${XeF}_{2}$ . The Xenon's electron configuration shifts to $s^{2}$ , $p^{5}$ , and $d_{1}$ , with two unpaired electrons. As a result, the core atom, Xe, hybridises in an $s p^{3} d$ manner. As a result, the ${XeF}_{2}$ molecule hybridization is $s p^{3} d$ .
The octet rule is broken by Xe. In fact, it bonds. It has a capacity of more than 8 electrons. Xenon can accommodate more than 8 electrons because it has valence electrons in the fourth energy level and access to the fourth sublevel.