Statement I: ${\mathrm{Ti}}^{+2}, {\mathrm{V}}^{+2}, {\mathrm{Cr}}^{+2}$ are good reducing agents 

Statement II: $\raisebox{1ex}{${\mathrm{E}}_{{\mathrm{M}}^{+3}}^{\mathrm{o}}$}\!\left/ \!\raisebox{-1ex}{${\mathrm{M}}^{+2}$}\right.$ is highly negative for the above species

${\mathrm{E}}_{{\mathrm{M}}^{+3}/{\mathrm{M}}^{+2}}$ of Ti, V and Cr is highly negative, so the ions Ti²⁺, V²⁺ and Cr²⁺ are strong reducing
agents and will liberate hydrogen from a dilute acid, e.g.,2 Cr²⁺(aq) + 2 H⁺(aq) $\to$ 2 Cr³⁺(aq) + H₂(g)