Statement: Roots of $x^2-8x+16=0$ are -4 , -4.

Choose the correct option.

For x = -4,

In $x^2+8x+16=0$,

L.H.S. = $(-4{)}^2+8(-4)+16=16-32+16=0$ = R.H.S

Therefore, Roots of $x^2-8x+16=0$ are -4 , -4 is true.

Note: Since both the roots are same, therefore this given quadratic equation has only one root.