Statement(I) : Bismuth shows a more stable '+3' state than '+5' state.
Statement(II) : Bismuth shows inert pair effect.

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Both (I) & (II) are true

Both (I) & (II) are false

(I) is false & (II) is true

(I) is true & (II) is false

answer is A.

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Detailed Solution

Due to Lanthanoid contraction , size increase from Sb to Bi is small.

In 'Bi' nuclear attraction over outermost electrons is more. Thus the paired 'ns' electrons are reluctant to uncouple and participate in bonding . Due to this reason 'Bi' shows an ox. state '+3' (corresponding to ground state) and it is unstable in higher ox. state(+5).

Compounds of 'Bi' in '+5' state (except BiF₅) are unstable and undergo reduction to form stable compounds with '+3' state.

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