Stationary point of y=x2+250x is

y=x2+250/x dy/dx=2x-250/x2y is minimum or maximum⇒dy/dx=02x=250/x2 x3=125 x=5 y=x2+250/x=25+250/5 =25+50 =75

Stationary point of y=x2+250x is

y=x2+250/x dy/dx=2x-250/x2y is minimum or maximum⇒dy/dx=02x=250/x2 x3=125 x=5 y=x2+250/x=25+250/5 =25+50 =75

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Stationary point of $y = x^{2} + \frac{250}{x} i s$

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(1, 51)

(5, 1)

(5, 25)

(5, 75)

answer is A.

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Detailed Solution

$y = x^{2} + 250 / x dy / dx = 2 x - 250 / x^{2}$

y is minimum or maximum

$\Rightarrow dy / dx = 0$

$2 x = 250 / x^{2} x^{3} = 125 x = 5 y = x^{2} + 250 / x = 25 + 250 / 5 = 25 + 50 = 75$

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Stationary point of $y = x^{2} + \frac{250}{x} i s$