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Stone projected at an angle $θ$ with horizontal from the roof of a tall building falls on the ground after three seconds. Two seconds after the projection it was again at the level of projection. Then the height of the building is $({g = 10 ms}^{-s})$

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15 m

5 m

25 m

20 m

answer is A.

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Detailed Solution

$\frac{2 u \sin θ}{g} = 2 \Rightarrow u \sin θ = 10 m s^{- 1};$

$h = (usinθ) t + \frac{1}{2} {gt}^{2} = 10 (1) + \frac{1}{2} 10 {(1)}^{2} = 15 m$

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