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Q.

Strong reducing behavior of H3PO2 is due to :

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a

high electron gain enthalpy of phosphorus

b

low oxidation state of phosphorus

c

presence of two —OH groups and one P—H bond

d

presence of one —OH group and two P—H bonds

answer is C.

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Detailed Solution

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strong reducing power of  H3PO2 is due to presence of one -OH group and two P-H bonds.so it has high tendency to release protons.

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