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Structure of ${Na}_{2} {[B_{4} O_{5} OH)}_{4}] \cdot 8 H_{2} O$ contains:

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two triangular and two tetrahedral units of boron

three triangular and one tetrahedral units of boron

four identical $B - O - B$ linkages

one peroxy linkage

answer is A.

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Detailed Solution

${Na}_{2} {[B_{4} O_{5} OH)}_{4}] \cdot 8 H_{2} O$ is Borax

It has two tetrahedral units and two triangular units.
The additional water molecules are connected to the metal ions, and the ion is $B_{4} O_{5} (OH)_{4}^{-}$

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