Subba Rao started work in 1995 at an annual salary of ₹5000 and received an increment of ₹200 each year. In which year did his income reach ₹7000?

Because there is a  ₹200 annual increase, Subba Rao's salary in 1995, 1996, and 1997 was ₹5000, ₹5200, and ₹5400 accordingly.

We get an AP.

So, a = 5000 and d = 200

Let after the n^th year, his salary be ₹7000.

Hence, aₙ = 7000

Using the n^th-term formula,

7000 = 5000 + (n - 1)200

200(n - 1) = 7000 - 5000

n - 1 = 2000/200

n = 10 + 1

n = 11

As a result, his salary reached ₹7,000 in the 11^th year. This suggests that after 10 years from 1995, 2005 will be the year.

In 2005, his income reached ₹7000.