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Substance $AzB (g)$ can undergo decomposition to form two set of products :
$AzB (g)$ $\to A_{2} (g) + B (g); {ΔH}^{\circ} = 40 kJ / mole$
$AzB (g)$ $\to A (g) + AB (g); {ΔH}^{\circ} = 50 kJ / mole$
If the molar ratio of $A_{2} (g)$ to $A (g)$ is 5 : 3 in a set of product gases, then the energy involved in the decomposition of 1 mole of $A_{2} B$ is:

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43.75 kJ/mol

48.73 kJ/mol

None of these

answer is A.

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Detailed Solution

Molar Ratio of A

: A = 5:3

For formatiation of 5 moles of A, the involved energy,

= 40 × 5 = 200 kJ

Similarly in formation of 3 moles of A energy required,

= 50×3=150kJ

Energy for decomposition of $A_{2} B$

= 200 + 150 = 350 KJ

Energy per mole

$\frac{350}{5 + 3} = 43.75 KJ / mole$

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