Substance Oxidation state of NA)HNO3I)– 3, + 5B)NH4NO3II)– 1/3C)N3HIII)+ 5D)H3PO3IV)+ 3 V)+ 1/3 (A)(B)(C)(D)1)IIIIIIIV2)VIIIIIIV3)IIIIIIIV4)IVIIIIIV

HNO3 ; (+1)+x+3(-2)=0 ⇒x=+5NH4NO3 ; NH4+; x+4(+1)=+1 ⇒x=-3NO3- ; x+3(-2)=-1⇒x=+5N3H ; 3x+(+1)=0 ⇒x=-1/3H3PO3 ; 3(+1)+x+3(-2)=0⇒x=+3

Substance Oxidation state of NA)HNO3I)– 3, + 5B)NH4NO3II)– 1/3C)N3HIII)+ 5D)H3PO3IV)+ 3 V)+ 1/3 (A)(B)(C)(D)1)IIIIIIIV2)VIIIIIIV3)IIIIIIIV4)IVIIIIIV

HNO3 ; (+1)+x+3(-2)=0 ⇒x=+5NH4NO3 ; NH4+; x+4(+1)=+1 ⇒x=-3NO3- ; x+3(-2)=-1⇒x=+5N3H ; 3x+(+1)=0 ⇒x=-1/3H3PO3 ; 3(+1)+x+3(-2)=0⇒x=+3

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Substance Oxidation state of N
A) HNO₃ I) – 3, + 5
B) NH₄NO₃ II) – 1/3
C) N₃H III) + 5
D) H₃PO₃ IV) + 3
V) + 1/3
(A) (B) (C) (D)
1) III I II IV
2) V II III IV
3) I II III IV
4) IV III II V

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Detailed Solution

HNO₃ ; (+1)+x+3(-2)=0 $\Rightarrow$ x=+5

NH₄NO₃ ;

${NH}_{4}^{+}; x + 4 (+ 1) = + 1 \Rightarrow x = - 3$

${NO}_{3}^{-}; x + 3 (- 2) = - 1 \Rightarrow x = + 5$

N₃H ; 3x+(+1)=0 $\Rightarrow$ x=-1/3

$H_{3} {PO}_{3}; 3 (+ 1) + x + 3 (- 2) = 0 \Rightarrow x = + 3$

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	Substance		Oxidation state of N
A)	HNO₃	I)	– 3, + 5
B)	NH₄NO₃	II)	– 1/3
C)	N₃H	III)	+ 5
D)	H₃PO₃	IV)	+ 3
		V)	+ 1/3

	(A)	(B)	(C)	(D)
1)	III	I	II	IV
2)	V	II	III	IV
3)	I	II	III	IV
4)	IV	III	II	V

Substance Oxidation state of NA)HNO3I)– 3, + 5B)NH4NO3II)– 1/3C)N3HIII)+ 5D)H3PO3IV)+ 3 V)+ 1/3 (A)(B)(C)(D)1)IIIIIIIV2)VIIIIIIV3)IIIIIIIV4)IVIIIIIV

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Substance Oxidation state of N
A) HNO₃ I) – 3, + 5
B) NH₄NO₃ II) – 1/3
C) N₃H III) + 5
D) H₃PO₃ IV) + 3
V) + 1/3
(A) (B) (C) (D)
1) III I II IV
2) V II III IV
3) I II III IV
4) IV III II V