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Q.

Substances that are oxidized and reduced in the following reaction are respectively N2H4(l) + 2 H2O2(l)→N2(g) +4 H2O(l)

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a

N2H4, H2O

b

N2H4, H2O2

c

N2 , H2O

d

H2O, N2

answer is B.

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Detailed Solution

\large \mathop {{N_2}}\limits^{ - 2} {H_4}\; + \;2{H_2}\mathop {{O_2}}\limits^{ - 1} \; \to \;\mathop {{N_2}}\limits^0 \; + \;4{H_2}\mathop O\limits^{ - 2}


Oxidation state of 'N' in N2H4 increased from -2 to zero
N2H4  Oxidized
Oxidation state of 'O' in H2O2 decreased from -1 to -2

H2O2  reduced

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