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Q.

Successive ionisation potentials of an element
M are 8.3, 25.1, 37.9, 259.3 and 340.1ev. The
formula of its bromide is

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a

MBr₄

b

MBr₅

c

MBr₃

d

MBr₂

answer is C.

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Detailed Solution

The mentioned ionisation potentials show that M element is a trivalent cation. Hence, their bromide will be ${MBr}_{3}$

Therefore, Option C is the correct answer.

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Successive ionisation potentials of an elementM are 8.3, 25.1, 37.9, 259.3 and 340.1ev. Theformula of its bromide is