Sucrose→hydrolysisA+B;Lactose→hydrolysisP+Q;Starch→hydrolysisX;Cellulose→hydrolysisY;Correct statements areI) A and B are a pair of functional isomersII) X and Y are a pair of anomerIII) P and Q are a pair of epimers

Sucrose→hydrolysisα−GlucoseA+β−FructoseBLactose→hydrolysisβ−GalactoseP+β−GlucoseQStarch→hydrolysisα−GlucoseXCellulose→hydrolysisβ−GlucoseYA and B are a pair of functional isomers because Glucose is an aldehyde and fructose is a ketoneAnomers are the stereoisomers that differ in only the anomeric carbon, the carbon that bears the aldehyde or ketone functional group. X and Y are a pair of anomersP and Q are a pair of epimers because Glucose and galactose differ from one another only at position C-4. Except C-4 position, they have an identical configuration in all other positions.

Sucrose→hydrolysisA+B;Lactose→hydrolysisP+Q;Starch→hydrolysisX;Cellulose→hydrolysisY;Correct statements areI) A and B are a pair of functional isomersII) X and Y are a pair of anomerIII) P and Q are a pair of epimers

Sucrose→hydrolysisα−GlucoseA+β−FructoseBLactose→hydrolysisβ−GalactoseP+β−GlucoseQStarch→hydrolysisα−GlucoseXCellulose→hydrolysisβ−GlucoseYA and B are a pair of functional isomers because Glucose is an aldehyde and fructose is a ketoneAnomers are the stereoisomers that differ in only the anomeric carbon, the carbon that bears the aldehyde or ketone functional group. X and Y are a pair of anomersP and Q are a pair of epimers because Glucose and galactose differ from one another only at position C-4. Except C-4 position, they have an identical configuration in all other positions.

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$S u c r o s e \overset{h y d r o l y s i s}{\to} A + B;$
$L a c t o s e \overset{h y d r o l y s i s}{\to} P + Q;$
$S t a r c h \overset{h y d r o l y s i s}{\to} X;$
$C e l l u l o s e \overset{h y d r o l y s i s}{\to} Y;$
Correct statements are
I) A and B are a pair of functional isomers
II) X and Y are a pair of anomer
III) P and Q are a pair of epimers

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I and III only

I only

I, II and III

II and III only

answer is C.

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Detailed Solution

$S u c r o s e \overset{h y d r o l y s i s}{\to} \underset{A}{α - G l u \cos e} + \underset{B}{β - F r u c t o s e}$

$L a c t o s e \overset{h y d r o l y s i s}{\to} \underset{P}{β - G a l a c t o s e} + \underset{Q}{β - G l u \cos e}$

$S t a r c h \overset{h y d r o l y s i s}{\to} \underset{X}{α - G l u \cos e}$

$C e l l u l o s e \overset{h y d r o l y s i s}{\to} \underset{Y}{β - G l u \cos e}$

A and B are a pair of functional isomers because Glucose is an aldehyde and fructose is a ketone
Anomers are the stereoisomers that differ in only the anomeric carbon, the carbon that bears the aldehyde or ketone functional group. X and Y are a pair of anomers
P and Q are a pair of epimers because Glucose and galactose differ from one another only at position C-4. Except C-4 position, they have an identical configuration in all other positions.

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