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Sudesh is twice as old as Seema. If six years is subtracted from Seema’s age and four years are added to Sudesh’s age, Sudesh will be four times Seema’s age. How old were they three years ago?

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25 & 11

65 & 42

29 & 32

41 & 48

answer is A.

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Detailed Solution

Concept: Suppose Seema's age is

x

.
Then Sudesh'w age is

2 x

.
If 6 years are subtracted from Seema's age we get

x - 6

and if 4 years are added to Sudesh's age we get

2 x + 4

So we are given that

2 x + 4 = 4 (x - 6) = > 2 x + 4 = 4 x - 24

= > 4 x - 2 x = 4 + 24

= > 2 x = 28

= > x = 14

=> Sudesh' age

= 2 x = 28

So, the current ages of Seema and Sudesh are 14 years and 28 years.
So, 3 years ago Seema was 11 years and Sudesh was 25 years
Hence, the correct Option is (1) 25 & 11.

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