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Sulphate of divalent metal M exists in hydrated form. If 0.10 mole of metal sulphate combines with 9.0 g of water to form the hydrated salt then, the formula of metal sulphate will be

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M S O_{4} . H_{2} O

M_{2} S O_{4} .2 H_{2} O

M_{2} S O_{4} .3 H_{2} O

M S O_{4} .5 H_{2} O

answer is D.

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Detailed Solution

0.1 moles Sulphate = 9 g of water

1 mole Sulphate = 90 g of water

1 mole of water= 18g of water.

9g of water= 0.5mole of water

Hence 5 moles of water will present in Sulphate.

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