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Sulphur exhibits + 6 oxidation state when it undergoes the hybridisation

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${SP}^{3} or SP$

${SP}^{3} or {SP}^{3} d^{2}$

${SP}^{3} d or {SP}^{3} d^{2}$

${SP}^{3} d or SP$

answer is B.

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Detailed Solution

S shows +6 oxidation in ${SF}_{6} ({SP}^{3} d^{2})$

$H_{2} {SO}_{4} ({SP}^{3})$ and in ${SO}_{3} ({SP}^{2})$

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