Sulphur trioxide is prepared by the following two reactions:S8(s)+8O2(g)⟶8SO2(g)2SO2(g)+O2(g)⟶2SO3(g)How many grams of SO3 are produced from 1 mol of S8?

1 mole S8(s) produces 8 moles SO3(g) i.e. 8×80g of SO3 i.e 640g of SO3.

1 mole S8(s) produces 8 moles SO3(g) i.e. 8×80g of SO3 i.e 640g of SO3.

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Sulphur trioxide is prepared by the following two reactions:
$\begin{matrix} S_{8} (s) + 8 O_{2} (g) ⟶ 8 {SO}_{2} (g) \\ 2 {SO}_{2} (g) + O_{2} (g) ⟶ 2 {SO}_{3} (g) \end{matrix}$
How many grams of ${SO}_{3}$ are produced from 1 mol of $S_{8}$ ?

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640.0

320.0

1280.0

960.0

answer is B.

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1 mole $S_{8 (s)}$ produces 8 moles ${SO}_{3 (g)}$

$i.e. 8 \times 80 g of {SO}_{3}$

$i.e 640 g of {SO}_{3}$ .

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