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Q.

Sulphur trioxide, ${SO}_{3}$ , is made by oxidizing sulphur dioxide, ${SO}_{2}$ , according to the equation, $2 {SO}_{2} + O_{2} ⟶ 2 {SO}_{3}$ . If a 16.0g sample of ${SO}_{2}$ yields 18.0g of ${SO}_{3}$ , what is the percent yield?

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a

$90.0 %$

b

$100 . %$

c

$\begin{aligned} 70.0 % \end{aligned}$

d

$\begin{aligned} 80.0 % \end{aligned}$

answer is C.

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Detailed Solution

$% y i e l d = \frac{n s o_{3}}{n s o_{2}} \times 100 = \frac{\frac{18}{80}}{\frac{16}{64}} \times 100 = 90 %$

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