Sulphuryl chloride, SO2Cl2, reacts with H2O to give mixture of H2SO4 and HCl. Aqueous solution of one mol SO2Cl2, will be neutralised by

SO2Cl2+2H2O→H2SO4+2HCl1mol H2SO4≡2NaOH2mol HCl≡2NaOH=4 mol NaOH1mol H2SO4≡1mol Ba(OH)22mol HCl≡1 mol Ba(OH)2⇒2 mol Ba(OH)2

Sulphuryl chloride, SO2Cl2, reacts with H2O to give mixture of H2SO4 and HCl. Aqueous solution of one mol SO2Cl2, will be neutralised by

SO2Cl2+2H2O→H2SO4+2HCl1mol H2SO4≡2NaOH2mol HCl≡2NaOH=4 mol NaOH1mol H2SO4≡1mol Ba(OH)22mol HCl≡1 mol Ba(OH)2⇒2 mol Ba(OH)2

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Sulphuryl chloride, SO₂Cl₂, reacts with H₂O to give mixture of H₂SO₄ and HCl. Aqueous solution of one mol SO₂Cl₂, will be neutralised by

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Both

None

2 mol of Ca(OH)₂

3 mol of NaOH

answer is B.

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Detailed Solution

${SO}_{2} {Cl}_{2} + 2 H_{2} O \to H_{2} {SO}_{4} + 2 HCl$

$\begin{matrix} 1 mol H_{2} {SO}_{4} \equiv 2 NaOH \\ 2 mol HCl \equiv 2 NaOH \end{matrix}] = 4 mol NaOH$

$\begin{matrix} 1 mol H_{2} {SO}_{4} \equiv 1 mol Ba {(OH)}_{2} \\ 2 mol HCl \equiv 1 mol Ba {(OH)}_{2} \end{matrix}] \Rightarrow 2 mol Ba {(OH)}_{2}$

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Sulphuryl chloride, SO2Cl2, reacts with H2O to give mixture of H2SO4 and HCl. Aqueous solution of one mol SO2Cl2, will be neutralised by

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Sulphuryl chloride, SO₂Cl₂, reacts with H₂O to give mixture of H₂SO₄ and HCl. Aqueous solution of one mol SO₂Cl₂, will be neutralised by