Sunlight of intensity $50 {\mathrm{Wm}}^{-2}$ is normally incident on the surface of a solar panel. Some part of incident energy $(25\%)$ is reflected from the surface and the rest is absorbed. The force exerted on $1 m^2$ surface area will be close to $\left(c=3\times {10}^8 {\mathrm{ms}}^{-1}\right)$