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Q.

Suppose a chemist has chosen 1020as the number of particles in a mole. Then the molecular mass of oxygen is

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a

53.2×10-3g

b

5.32×10-3g

c

532×10-4g

d

0.532×10-3g

answer is A.

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Detailed Solution

Molecular mass of oxygen is 32 g. means 32g oxygen contain 23 2 6.023 10 O  molecules.

32g of O2 ______ 6.023 ×1023O2 molecules

MM of O2x-----1020O2 molecules

x×6.023×1023=32×1020 

x32×10206.023×1023

x5.32×10-3g

Hence mass of 1020 molecules of O2 is 5.32×10-3g.

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Suppose a chemist has chosen 1020as the number of particles in a mole. Then the molecular mass of oxygen is