Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Suppose a chemist has chosen 1020as the number of particles in a mole. Then the molecular mass of oxygen is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

53.2×10-3g

b

5.32×10-3g

c

532×10-4g

d

0.532×10-3g

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Molecular mass of oxygen is 32 g. means 32g oxygen contain 23 2 6.023 10 O  molecules.

32g of O2 ______ 6.023 ×1023O2 molecules

MM of O2x-----1020O2 molecules

x×6.023×1023=32×1020 

x32×10206.023×1023

x5.32×10-3g

Hence mass of 1020 molecules of O2 is 5.32×10-3g.

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring