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Suppose a compound contains atoms A, B and C. The oxidation number of A is +2, B is +5 and C is –2.
The possible formula of the compound would be

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$A B C_{2}$

$A B C_{3}$

$A_{3} {(B C_{4})}_{2}$

$A_{3} {(B_{4} C)}_{2}$

answer is C.

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Detailed Solution

$3 \times 2 + 2 \times 5 + 8 \times - 2 = 16 - 16 = 0$

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