Q.

Suppose a  88226Ra nucleus at rest and in ground state undergoes  αdecay  to  a 86222Rn nucleus. Find the kinetic energy of the emitted  particle (in MeV).  [Given: atomic mass of  88226Ra=226.005u, atomic mass of  86222Rn=222.000u, atomic mass of α particle=4.000u, 1u=931  MeV/c2, c is speed of the light, Take 222226=0.98]

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answer is 4.56.

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Detailed Solution

Q=(MRaMRnMα)c2

=931×51000=4.655MeV

Kα=A4AQ=222226×4.655=0.98×4.655=4.56MeV

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