Suppose that we change Urms of gas in a closed container from 5×10−2cm/sec to 10×10−2cm/sec which one of the following might correctly explain how this change was accomplished?

We know thatURMS=SRTM⇒U2U1=T2T1 ⇒10×102cm/sec5×102cm/sec=T2T1⇒T2T1=41Again, CRMS=3PP⇒P2P1=41We triple the pressure by heating the gas.

Suppose that we change Urms of gas in a closed container from 5×10−2cm/sec to 10×10−2cm/sec which one of the following might correctly explain how this change was accomplished?

We know thatURMS=SRTM⇒U2U1=T2T1 ⇒10×102cm/sec5×102cm/sec=T2T1⇒T2T1=41Again, CRMS=3PP⇒P2P1=41We triple the pressure by heating the gas.

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Suppose that we change $U_{rms}$ of gas in a closed container from $5 \times 10^{- 2} cm / \sec to 10 \times 10^{- 2} cm / \sec$ which one of the following might correctly explain how this change was accomplished?

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By heating the gas we double the temperature.

By removing 75% of the gas at constant volume we decrease the pressure to one quarter of its original value

By heating the gas we quadruple the pressure.

By pumping in more gas. at constant temperature we quadruple the pressure.

answer is C.

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Detailed Solution

We know that

$U_{RMS} = \sqrt{\frac{SRT}{M}} \Rightarrow \frac{U_{2}}{U_{1}} = \sqrt{\frac{T_{2}}{T_{1}}} \begin{array}{l} \Rightarrow \frac{10 \times 10^{2} cm / \sec}{5 \times 10^{2} cm / \sec} = \sqrt{\frac{T_{2}}{T_{1}}} \\ \Rightarrow \frac{T_{2}}{T_{1}} = \frac{4}{1} \end{array}$