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Q.

Suppose two deuterons must get as close as 10-14 m in order for the nuclear force to overcome the repulsive electrostatic force. The height of the electrostatic barrier is nearest to

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a

2.3 MeV

b

0.14 MeV

c

0.56 MeV

d

1.8 MeV

answer is A.

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Detailed Solution

deutron is having one proton + one neutron 

so charge of deutron is 1.602×10-19 C

Barrier height

 =14πε0e2reJ=14πε0ereeV

 =9×109×1.6×10−1910−14eV=1.44×105eV  =0.14MeV

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