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Surface temperature of a hot body is $T_{1}$ and variation of spectral radiancy $(R_{λ})$ with wave length is as shown in figure. Energy of individual photon at maximum spectral radiancy is E. If the temperature of the body is increased from $T_{1} and T_{2}$ , Then energy of individual photon, at maximum spetral radiancy is $E'$ , Then

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$E' = E$

Informations are not sufficient to find a relation between E and $E'$

$E' < E$

$E' > E$

answer is D.

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Detailed Solution

Initially let $(R_{λ})$ is maximum at wave length $λ$

$∴ E = \frac{hc}{λ}$

When temperature is increased, $(R_{λ})$ becomes maximum at shorter wave length $λ' (λ' < λ)$

$∴ E' = \frac{hc}{λ'} > E$

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