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Symmetric form of the line passing through P ( 2, 2 ) having slope ' 1 ' is

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$\frac{x + 2}{\cos \frac{π}{4}} = \frac{y + 2}{\sin \frac{π}{4}}$

$\frac{x - 2}{\cos \frac{π}{4}} = \frac{y - 2}{\sin \frac{π}{4}}$

$\frac{x + 2}{\cos \frac{π}{3}} = \frac{y + 2}{\sin \frac{π}{3}}$

$\frac{x - 2}{\cos \frac{π}{3}} = \frac{y - 2}{\sin \frac{π}{3}}$

answer is B.

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Detailed Solution

p(2,2) m = tan $θ$ = 1; $θ = \frac{π}{4}$

equation of line in symmetric form

$\Rightarrow$ $\frac{x - x_{1}}{\cos θ} = \frac{y - y_{1}}{\sin θ}$

$\Rightarrow$ $\frac{x - 2}{\cos \frac{π}{4}} = \frac{y - 2}{\sin \frac{π}{4}}$

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