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Q.

Take 100 g of hot water at $80^{0} C$ in thermos flask. Add 200 g of cold water at $20^{0} C$ in the thermos flask. Stir the contents and measure the temperature of the mixture. Then, the resultant temperature is [No heat lost or gained]

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a

$80^{0} C$

b

$40^{0} C$

c

$20^{0} C$

d

$60^{0} C$

answer is A.

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Detailed Solution

$m_{1} = 100 g, T_{1} = 80^{0} C m_{2} = 200 g, T_{2} = 20^{0} C, T = ? Q_{L} = Q_{g} \Rightarrow m_{1} s_{w} (T_{1} - T) = m_{2} s_{w} (T - T_{2}) \Rightarrow 100 \times 1 (180 - T) = 200 \times 1 (T - 20) \Rightarrow 80 - T = 2 T - 40 3 T = 120 ∴ T = 40^{0} C$

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Take 100 g of hot water at 800C in thermos flask. Add 200 g of cold water at 200C in the thermos flask. Stir the contents and measure the temperature of the mixture. Then, the resultant temperature is [No heat lost or gained]