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Taking earth to be a metallic sphere, its capacity will approximately be

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$700 F$

$711 μ F$

$6.4 \times 10^{6} F$

$700 p F .$

answer is C.

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Detailed Solution

$C = 4 π \in_{0} R,$ where $R = 6.4 \times 10^{6} m$

$= \frac{6.4 \times 10^{6}}{9 \times 10^{9}} = 711 μ F$

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