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Taking $R=1k Ω and E=250 V$ in figure, the magnitude of the current, in the horizontal wire between a and e is $x ×10mA.$ Find value of $x$ .

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Detailed Solution

Current in ab = $\frac{E}{25 R}$

Current in ed = $\frac{13 E}{25 R}$

Current in ca = $\frac{6 E}{25 R}$

Current in ce = $\frac{8 E}{25 R}$

Current in ae = $\frac{5 E}{25 R} = 50 m A$

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