Taking Rydberg’s constant $R_{H} = 1 .097 \times 10^{7} m$ first and second wavelength of Balmer series in hydrogen spectrum is

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2000 $\overset{o}{A}$ , 3000 $\overset{o}{A}$

1575 $\overset{o}{A}$ , 2960 $\overset{o}{A}$

6529 $\overset{o}{A}$ , 4280 $\overset{o}{A}$

6552 $\overset{o}{A}$ , 4863 $\overset{o}{A}$

answer is D.

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Detailed Solution

$\frac{1}{λ} = R [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] . {For first wavelength}_{n} n_{1} = 2, n_{2} = 3 \Rightarrow λ_{1} = 6563 \overset{o}{A} . For second wavelength, n_{1} = 2, n_{2} = 4 \Rightarrow λ_{2} = 4861 \overset{o}{A}$

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