Taking that earth revolves round the sun in circular orbit of radius $15 \times 10^{10} m$ with a time period of 1 year. The time taken by another planet which is at a distance of $540 \times 10^{10} m$ , to revolve round the sun in circular orbit once will be

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36 years

72 years

144 years

216 years

answer is A.

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Detailed Solution

$\begin{array}{l} T \propto R^{3 / 2} \\ \frac{1}{T} = {(\frac{15 \times 10^{10}}{540 \times 10^{10}})}^{3 / 2} = \frac{1}{216} \\ T = 216 years \end{array}$

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