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Q.

Tan1(13)+Tan1(29)+Tan1(433)+...Infinite terms

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a

π

b

π4

c

2π

d

π2

answer is A.

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Detailed Solution

Tn=tan1(2n11+22n1)   =tan1(2n2n11+2n.2n1)=tan12ntan12n1 S=n=1Tn=tan1tan11

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