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Q.

tan12°.tan24°.tan48°.tan84°=

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a

13

b

1

c

1

d

3

answer is A.

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Detailed Solution

tanθ.tan(60θ).tan(60+θ)=tan3θ

=tan12.tan(6012).tan(60+12)tan24.tan(6024)tan(60+24)tan(60+12)tan(6024)

=tan3(12).tan3(24)tan72.tan36

=tan36.tan72tan72.tan36

=1

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