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Q.

tan θ+2 tan 2θ+4 tan 4θ+8 tan 8θ+16 tan 16θ+32 cot 32θ=

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a

sin θ

b

cos θ

c

tan θ

d

cot θ

answer is D.

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Detailed Solution

cotθ-tanθ=2cot2θ tan θ+2 tan 2θ+4 tan 4θ+8 tan 8θ+16 tan 16θ+32 cot 32θ =cotθ-2cot2θ+2(cot2θ-2cot4θ)+4(cot4θ-2cot8θ)+8(cot8θ-2cot16θ) +16(cot16θ-2cot32θ)+32cot32θ =cotθ

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