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tanAtanB=xand cotBcotA=4, then cot(AB)=

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By Expert Faculty of Sri Chaitanya
a
1x+1y 
b
1x1y
c
1xy
d
x+y
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detailed solution

Correct option is A

y=cotBcotA=1tanB1tanA=xtanAtanB

tanAtanB=xy

Now, 

cot(AB)=1tan(AB)

=1+tanAtanBtanAtanB=1+xyx=1x+1y

 

 


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