Tangential acceleration on a bob of a simple pendulum of mass 100 grams when its amplitude is 1o is (here g=10m/s2)

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Tangential acceleration on a bob of a simple pendulum of mass 100 grams when its amplitude is $1^{o}$ is (here g=10m/ $s^{2}$ )

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$0.017 m / s e c^{2}$

$1.7 m / s e c^{2}$

$0.17 m / s e c^{2}$

$0.034 m / s e c^{2}$

answer is C.

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Detailed Solution

Tangential acceleration $a_{T} =gsinθ$

$a_{T} =gθ because (sinθ ≃ θ) if θ is very small = 10×π/180 ({here θ=1}^{o} =π/180 radian) a_{T} = \frac{3.14}{18} {=0.17 m/sec}^{2}$

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