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Q.

Tangents to the ellipse x2a2+y2b2=1 make angles θ1 and θ2 with the major axis of the ellipse such that tan θ1 + θ2 = k constant. The locus of the pt. of intersection of the tangents (x2  a2)  (y2  b2) = 

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a

k2xy

b

xyk

c

kxy

d

2kxy

answer is B.

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Detailed Solution

Let y=mx±a2m2+b2 be tangent drawn through the point (x1,y1) m2(x12-a2)-2mx1y1+y12-b2 =0 Let m1=Tanθ1   m2=Tanθ2 m1+m2=2x1y1x12-a2 m1m2=y12-b2x12-a2 Tan(θ1+θ2)=k m1+m21-m1m2=k 2x1y1x12-a21-y12-b2x12-a2=k 2x1y1x12-a2-y12+b2=k locus of (x1,y1) is 2xy=kx2-y2-a2+b2

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