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Tanks A and B open at the top contain two different liquids upto certain height in them. A hole is made on the wall of each tank at a depth 'h' from the surface of the liquid. The area of the hole in 'A' is twice that of in B. If the liquid mass flux through each hole is equal, then the ratio of the densities of the liquids respectively is

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2/1

3/2

2/3

1/2

answer is D.

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Detailed Solution

$m / t = constant; ρ_{1} A_{1} V = ρ_{2} A_{2} V \Rightarrow ρ_{1} A_{1} = ρ_{2} A_{2}$

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