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Q.

Taxi charges in a city consist of fixed charges per day and the remaining depending upon the distance travelled in kilometers. If a person travels 110 km, he pays Rs. 690, and for travelling 200 km, he pays Rs. 1050. Find the fixed charges per day and the rate per km.


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a

Fixed charges=Rs. 250 and Rate per kilometer =Rs. 40

b

Fixed charges=Rs. 230 and Rate per kilometer =Rs. 40

c

Fixed charges=Rs. 220 and Rate per kilometer =Rs. 40

d

Fixed charges=Rs. 210 and Rate per kilometer =Rs. 40 

answer is A.

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Detailed Solution

It is given that a person travels 110 km, he pays Rs.690 and for travelling 200 km, he pays Rs.1050.
Let, fixed charge be Rs.x and the rate per kilometer = Rs.y.
Then,
x+110y=690      ... 1    x+200y=1050      ... 2  
Now from equation (1)
x=690-110y     … (3)
Substitute the value of x=690-110y in equation (2)
  x + 200y = 1050 690−110y + 200y = 1050 690+ 90y = 1050 90y = 1050−690 90y=360 y= 360 90 y=40  
Putting the value of y = 40 in equation (3) to find the value of x:
x=690−110y x=690−110 40 x=690−440 x=250  
Therefore, the fixed charges are Rs. 250 and the rate per kilometer are Rs.40.
Hence, option (1) is correct.
 
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