Team ‘A’ consists of 7 boys and n girls and Team ‘B’ has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to

Number of boys in team A = 7

Number of girls in team A  = n

Number of boys in team B = 4

Number of girls in team  B = 6

Number of games boys play against and girl play against a girl = 52

$$\begin{gathered} 7\times 4+\mathrm{n}\times 6=52 \\ \Rightarrow 6\mathrm{n}=52-28 \\ \Rightarrow 6\mathrm{n}=24 \end{gathered}$$

$\Rightarrow \boxed{ \mathrm{n}=4 }$