${\mathrm{TeCl}}_4$ is expected to be

Total number of electron pair $=\frac{6+4}{2}=5$

Total number of bond pair $=5$

Total number of lone pair $=(5-4)=1$

Hybridisation $={\mathrm{sp}}^3\mathrm{ }\mathrm{d}$

Thus, the predicted shape is trigonal bipyramidal but due to 1 lone pair it is see- saw in shape.