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Temperature versus pressure graph of an ideal gas is shown in the given figure. During the process AB,

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internal energy of the gas remains constant

volume of the gas is increased

work done by the atmosphere on the gas is positive

pressure is inversely proportional to volume

answer is A, C, D.

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Detailed Solution

T = constant

PV = constant (Boyle's law)

or $P \propto \frac{1}{V}$

Pressure of the gas is increasing. Therefore, volume should decrease. Work done by the gas is negative or work done on the gasby the atmosphere is positive. Internal energy will remain constant.

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