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Q.

Ten coins are placed on top of each other on a horizontal table. If the mass of each coin is 10g and acceleration due to gravity is 10 ms-2, what is the magnitude and direction of the force on the 7th coin ( counted from the bottom) due to all the coins above it ?

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a

0.3N downwards

b

0.3N upwards

c

0.7N downwards

d

0.7N upwards

answer is A.

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Detailed Solution

Three coins are above the 7th coin. Therefore, force from 3 coins above it will be 

3mg=310×10-310=0.3N(in downward direction)

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