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Ten IIT and 2IIIT students sit in a round table. The number of ways in which exactly 3IIT students are sit in between 2IIIT students is____

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$10 P_{3} \times 2! \times 8!$

$10 P_{3} \times 3! \times 8!$

$10 P_{3} \times 2! \times 7!$

answer is B.

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Detailed Solution

$2 IIIT students are arranged in 2! Ways$
$3 IIIT students c a n b e arranged in b e t w e e n 2 I I I T s t u d e n t s i s 10 P_{3}$
$Req . no ways$ $10 P_{3} \times 2! \times 7!$

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