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Q.

Tertiary butyl methyl ether on treatment with HI forms 

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a

 Isobutane and Methyl Iodine
 

b

 Isobutanol and Methanol
 

c

Tertiary Botyl Iodide and Methyl Iodide

d

 Tertiary Butyl Iodide and Methanol
 

answer is C.

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Detailed Solution

The SN1 reaction mechanism proceeds step-by-step, starting with the formation of the carbocation through the elimination of the leaving group. The nucleophile then attacks the carbocation. Finally, the protonated nucleophile is deprotonated to produce the desired product.

The SN1 process was pursued because the stable tertiary carbocation formed. Iodine is joined to the tertiary C atom, and the methyl group is joined to the -OH group.

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Tertiary butyl methyl ether on treatment with HI forms